olymmath

USAJMO 2015

United States of America Junior Mathematical Olympiad 2015.

Day 1

Problem 1

  • Day 1

Given a sequence of real numbers, a move consists of choosing two terms and replacing each with their arithmetic mean. Show that there exists a sequence of 2015 distinct real numbers such that after one initial move is applied to the sequence -- no matter what move -- there is always a way to continue with a finite sequence of moves so as to obtain in the end a constant sequence.

Answer, solutions and source

Problem 2 · Also USAMO 2015 Problem 1

  • Day 1

Solve in integers the equation x2+xy+y2=(x+y3+1)3.x^2+xy+y^2 = \left(\frac{x+y}{3}+1\right)^3.

Answer, solutions and source

Problem 3 · Also USAMO 2015 Problem 2

  • Day 1

Quadrilateral APBQAPBQ is inscribed in circle ω\omega with ∠P=∠Q=90∘\angle P = \angle Q = 90^{\circ} and AP=AQ<BPAP = AQ < BP . Let XX be a variable point on segment PQ‾\overline{PQ} . Line AXAX meets ω\omega again at SS (other than AA ). Point TT lies on arc AQBAQB of ω\omega such that XT‾\overline{XT} is perpendicular to AX‾\overline{AX} . Let MM denote the midpoint of chord ST‾\overline{ST} . As XX varies on segment PQ‾\overline{PQ} , show that MM moves along a circle.

Answer, solutions and source

Day 2

Problem 4

  • Day 2

Find all functions f:Q→Qf:\mathbb{Q}\rightarrow\mathbb{Q} such thatf(x)+f(t)=f(y)+f(z)f(x)+f(t)=f(y)+f(z)for all rational numbers x<y<z<tx<y<z<t that form an arithmetic progression. ( Q\mathbb{Q} is the set of all rational numbers.)

Answer, solutions and source

Problem 5

  • Day 2

Let ABCDABCD be a cyclic quadrilateral. Prove that there exists a point XX on segment BD‾\overline{BD} such that ∠BAC=∠XAD\angle BAC=\angle XAD and ∠BCA=∠XCD\angle BCA=\angle XCD if and only if there exists a point YY on segment AC‾\overline{AC} such that ∠CBD=∠YBA\angle CBD=\angle YBA and ∠CDB=∠YDA\angle CDB=\angle YDA .

Answer, solutions and source

Problem 6 · Also USAMO 2015 Problem 4

  • Day 2

Steve is piling m≥1m\geq 1 indistinguishable stones on the squares of an n×nn\times n grid. Each square can have an arbitrarily high pile of stones. After he finished piling his stones in some manner, he can then perform stone moves, defined as follows. Consider any four grid squares, which are corners of a rectangle, i.e. in positions (i,k),(i,l),(j,k),(j,l)(i, k), (i, l), (j, k), (j, l) for some 1≤i,j,k,l≤n1\leq i, j, k, l\leq n , such that i<ji<j and k<lk<l . A stone move consists of either removing one stone from each of (i,k)(i, k) and (j,l)(j, l) and moving them to (i,l)(i, l) and (j,k)(j, k) respectively, or removing one stone from each of (i,l)(i, l) and (j,k)(j, k) and moving them to (i,k)(i, k) and (j,l)(j, l) respectively.

Two ways of piling the stones are equivalent if they can be obtained from one another by a sequence of stone moves.

How many different non-equivalent ways can Steve pile the stones on the grid?

Answer, solutions and source