olymmath

US-TST 2018 Problem 1

    Let n≥2n \geq 2 be a positive integer, and let σ(n)\sigma(n) denote the sum of the positive divisors of nn. Prove that the nth n^{\text {th }} smallest positive integer relatively prime to nn is at least σ(n)\sigma(n), and determine for which nn equality holds.

    Dataset text NuminaMath olympiads. Quoted with source.

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