olymmath

TSTST 2023 Problem 9

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Let pp be a fixed prime and let a≥2a \geq 2 and e≥1e \geq 1 be fixed integers. Given a function f:Z/aZ→Z/peZf: \mathbb{Z} / a \mathbb{Z} \rightarrow \mathbb{Z} / p^{e} \mathbb{Z} and an integer k≥0k \geq 0, the kk th finite difference, denoted Δkf\Delta^{k} f, is the function from Z/aZ\mathbb{Z} / a \mathbb{Z} to Z/peZ\mathbb{Z} / p^{e} \mathbb{Z} defined recursively by Δ0f(n)=f(n)Δkf(n)=Δk−1f(n+1)−Δk−1f(n) for k=1,2,…\begin{aligned} & \Delta^{0} f(n)=f(n) \\ & \Delta^{k} f(n)=\Delta^{k-1} f(n+1)-\Delta^{k-1} f(n) \text { for } k=1,2, \ldots \end{aligned} Determine the number of functions ff such that there exists some k≥1k \geq 1 for which Δkf=f\Delta^{k} f=f 。

Dataset text NuminaMath olympiads. Quoted with source.

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p^{e\left(a-p^{\nu_{p}(a)}\right)}

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