olymmath

TSTST 2023 Problem 1

    Let ABCA B C be a triangle with centroid GG. Points RR and SS are chosen on rays GBG B and GCG C, respectively, such that ∠ABS=∠ACR=180∘−∠BGC.\angle A B S=\angle A C R=180^{\circ}-\angle B G C . Prove that ∠RAS+∠BAC=∠BGC\angle R A S+\angle B A C=\angle B G C.

    Dataset text NuminaMath olympiads. Quoted with source.

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