olymmath

RU-ALLRUSSIAN 1990 Problem 14

    A, B, C are adjacent vertices of a regular 2n- gon and D is the vertex opposite to B (so that BD passes through the center of the 2n- gon). X is a point on the side AB and Y is a point on the side BC so that angle XDY = π/2n. Show that DY bisects angle XYC.

    Dataset text NuminaMath olympiads. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Locator ru-allrussian/1990/p14 · Tag W1801PDC1P · Edit this page on GitHub · Keys: j next, k previous