RU-ALLRUSSIAN 1989 Problem 18
ABC is a triangle. Points D, E, F are chosen on BC, CA, AB such that B is equidistant from D and F, and C is equidistant from D and E. Show that the circumcenter of AEF lies on the bisector of EDF.
Dataset text NuminaMath olympiads. Quoted with source.
Solutions
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