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RU-ALLRUSSIAN 1987 Problem 8

    A1,A2,…,A2m+1\mathrm{A_1,A_2,\ldots,A_{2m + 1}} and B1,B2,…,B2n+1\mathbf{B}_1,\mathbf{B}_2,\ldots ,\mathbf{B}_{2n + 1} are points in the plane such that the 2m+2n+22\mathrm{m} + 2\mathrm{n} + 2 lines A1A2,A2A3,…,A2mA2m+1,A2m+1A1,B1B2,B2B3,…,B2nB2n+1,B2n+1B1\mathrm{A_1A_2,A_2A_3,\ldots,A_{2m}A_{2m + 1},A_{2m + 1}A_1,B_1B_2,B_2B_3,\ldots,B_{2n}B_{2n + 1},B_{2n + 1}B_1} are all different and no three of them are concurrent. Show that we can find i and j such that AiAi+1\mathrm{A_iA_{i + 1}} BiBj+1\mathrm{B_iB_{j + 1}} are opposite sides of a convex quadrilateral (if i=2m+1\mathrm{i} = 2\mathrm{m} + 1 , then we take Ai+1\mathrm{A_{i + 1}} to be A1\mathrm{A_1} . Similarly for j=2n+1\mathrm{j} = 2\mathrm{n} + 1 ).

    Dataset text NuminaMath olympiads. Quoted with source.

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