olymmath

RU-ALLRUSSIAN 1987 Problem 3

    ABCDEFG is a regular 7- gon. Prove that 1/AB=1/AC+1/AD1 / \mathrm{AB} = 1 / \mathrm{AC} + 1 / \mathrm{AD} .

    Dataset text NuminaMath olympiads. Quoted with source.

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