olymmath

RU-ALLRUSSIAN 1985 Problem 14

    The points A, B, C, D, E, F are equally spaced on the circumference of a circle (in that order) and AF is a diameter. The center is O. OC and OD meet BE at M and N respectively. Show that MN+CD=OA\mathrm{MN} + \mathrm{CD} = \mathrm{OA} .

    Dataset text NuminaMath olympiads. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Locator ru-allrussian/1985/p14 · Tag NKEW0818HN · Edit this page on GitHub · Keys: j next, k previous