olymmath

RU-ALLRUSSIAN 1984 Problem 7

    n>3\mathrm{n} > 3 positive integers are written in a circle. The sum of the two neighbours of each number divided by the number is an integer. Show that the sum of those integers is at least 2n and less than 3n. For example, if the numbers were 3, 7, 11, 15, 4, 1, 2 (with 2 also adjacent to 3), then the sum would be 14/7+22/11+15/15+16/4+6/1+4/2+9/3=2014 / 7 + 22 / 11 + 15 / 15 + 16 / 4 + 6 / 1 + 4 / 2 + 9 / 3 = 20 and 14≤20<2114 \leq 20 < 21 .

    Dataset text NuminaMath olympiads. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Locator ru-allrussian/1984/p7 · Tag 4RWY6JBDAM · Edit this page on GitHub · Keys: j next, k previous