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RU-ALLRUSSIAN 1983 Problem 8

    A and B are acute angles such that sin⁡2A+sin⁡2B=sin⁡(A+B)\sin^{2} \mathrm{A} + \sin^{2} \mathrm{B} = \sin (\mathrm{A} + \mathrm{B}) . Show that A+B=π/2\mathrm{A} + \mathrm{B} = \pi / 2 .

    Dataset text NuminaMath olympiads. Quoted with source.

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