olymmath

RU-ALLRUSSIAN 1983 Problem 6

    M is the midpoint of BC. E is any point on the side AC and F is any point on the side AB. Show that area MEF≤\mathrm{MEF} \leq area BMF+\mathrm{BMF} + area CME.

    Dataset text NuminaMath olympiads. Quoted with source.

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