olymmath

RU-ALLRUSSIAN 1982 Problem 4

    A non- negative real is written at each vertex of a cube. The sum of the eight numbers is 1. Two players choose faces of the cube alternately. A player cannot choose a face already chosen or the one opposite, so the first player plays twice, the second player plays once. Can the first player arrange that the vertex common to all three chosen faces is ≤1/6\leq 1 / 6 ?

    Dataset text NuminaMath olympiads. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Locator ru-allrussian/1982/p4 · Tag JD0FBCGKTM · Edit this page on GitHub · Keys: j next, k previous