Let x n = ( 1 + 2 + 3 ) n \mathbf{x}_{\mathrm{n}} = (1 + \sqrt{2} + \sqrt{3})^{\mathrm{n}} x n = ( 1 + 2 + 3 ) n . We may write x n = a n + b n 2 + c n 3 + d n 6 \mathbf{x}_{\mathrm{n}} = \mathbf{a}_{\mathrm{n}} + \mathbf{b}_{\mathrm{n}}\sqrt{2} + \mathbf{c}_{\mathrm{n}}\sqrt{3} + \mathbf{d}_{\mathrm{n}}\sqrt{6} x n = a n + b n 2 + c n 3 + d n 6 , where a n , b n , c n , d n \mathbf{a}_{\mathrm{n}}, \mathbf{b}_{\mathrm{n}}, \mathbf{c}_{\mathrm{n}}, \mathbf{d}_{\mathrm{n}} a n , b n , c n , d n are integers. Find the limit as n \mathbf{n} n tends to infinity of b n / a n , c n / a n , d n / a n \mathbf{b}_{\mathrm{n}} / \mathbf{a}_{\mathrm{n}}, \mathbf{c}_{\mathrm{n}} / \mathbf{a}_{\mathrm{n}}, \mathbf{d}_{\mathrm{n}} / \mathbf{a}_{\mathrm{n}} b n / a n , c n / a n , d n / a n .