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RU-ALLRUSSIAN 1967 Problem 1

    In the acute- angled triangle ABC, AH is the longest altitude (H lies on BC), M is the midpoint of AC, and CD is an angle bisector (with D on AB).

    (a) If AH<=BM\mathrm{AH}< = \mathrm{BM} , prove that the angle ABC<=60\mathrm{ABC}< = 60 .

    (b) If AH=BM=CD\mathrm{AH} = \mathrm{BM} = \mathrm{CD} , prove that ABC is equilateral.

    Dataset text NuminaMath olympiads. Quoted with source.

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