Home Competitions RU-ALLRUSSIAN 1966 Problem 6
RU-ALLRUSSIAN 1966 Problem 6
Given non- negative real numbers a 1 \mathrm{a_1} a 1 , a 2 \mathrm{a_2} a 2 , ..., a n \mathrm{a_n} a n , such that a i − 1 ≤ a i ≤ 2 a i − 1 \mathrm{a_{i - 1}} \leq \mathrm{a_i} \leq 2\mathrm{a_{i - 1}} a i − 1 ≤ a i ≤ 2 a i − 1 for i = 2 , 3 , … , n i = 2,3,\ldots ,\mathrm{n} i = 2 , 3 , … , n . Show that you can form a sum s = b 1 a 1 + … + b n a n \mathrm{s} = \mathrm{b_1a_1} + \ldots +\mathrm{b_na_n} s = b 1 a 1 + … + b n a n with each b i + 1 \mathrm{b_i} + 1 b i + 1 or - 1, so that 0 ≤ s ≤ a 1 0 \leq \mathrm{s} \leq \mathrm{a_1} 0 ≤ s ≤ a 1 .
Dataset text NuminaMath olympiads . Quoted with source.
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