olymmath

RU-ALLRUSSIAN 1964 Problem 6

  • Answer

Find all possible integer solutions for sqrt(x+sqrt(x…(x+sqrt(x))…))=y\mathrm{sqrt(x + sqrt(x\ldots(x + sqrt(x)) \ldots)) = y} , where there are 1998 square roots.

Dataset text NuminaMath olympiads. Quoted with source.

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x = 0, y = 0

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