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RU-ALLRUSSIAN 1964 Problem 11

  • Answer

The natural numbers a, b, n are such that for every natural number k not equal to b, b - k divides a - kn\mathrm{k^n} . Prove that a=bn\mathrm{a} = \mathrm{b^n} .

Dataset text NuminaMath olympiads. Quoted with source.

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a = b^n

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