RU-ALLRUSSIAN 1962 Problem 1
ABCD is any convex quadrilateral. Construct a new quadrilateral as follows. Take A' so that A is the midpoint of DA'; similarly, B' so that B is the midpoint of AB'; C' so that C is the midpoint of BC'; and D' so that D is the midpoint of CD'. Show that the area of A'B'C'D' is five times the area of ABCD.
Dataset text NuminaMath olympiads. Quoted with source.
Solutions
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