olymmath

Putnam 2018 B3

  • Session B

Find all positive integers n<10100n < 10^{100} for which simultaneously nn divides 2n2^n, n−1n-1 divides 2n−12^n-1, and n−2n-2 divides 2n−22^n - 2.

Curated text Kedlaya Putnam archive. Quoted with source.

Solutions

Human solution Solution 1 by Kiran Kedlaya and Lenny Ng

The terms of the source let olymmath link to this solution but not copy it. Read the solution (Kedlaya Putnam archive).

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