olymmath

Putnam 2013 A6

  • Session A

Define a function w:Z×Z→Zw : \mathbb{Z} \times \mathbb{Z} \to \mathbb{Z} as follows. For ∣a∣,∣b∣≤2|a|, |b| \leq 2, let w(a,b)w(a, b) be as in the table shown; otherwise, let w(a,b)=0w(a, b) = 0.

w(a,b)b=−2b=−1b=0b=1b=2a=−2−1−22−2−1a=−1−24−44−2a=02−412−42a=1−24−44−2a=2−1−22−2−1\begin{array}{c|ccccc} w(a,b) & b=-2 & b=-1 & b=0 & b=1 & b=2 \\ \hline a=-2 & -1 & -2 & 2 & -2 & -1 \\ a=-1 & -2 & 4 & -4 & 4 & -2 \\ a=0 & 2 & -4 & 12 & -4 & 2 \\ a=1 & -2 & 4 & -4 & 4 & -2 \\ a=2 & -1 & -2 & 2 & -2 & -1 \\ \end{array}

For every finite subset SS of Z×Z\mathbb{Z} \times \mathbb{Z}, define A(S)=∑(s,s′)∈S×Sw(s−s′).A(S) = \sum_{(\mathbf{s}, \mathbf{s}') \in S \times S} w(\mathbf{s} - \mathbf{s}'). Prove that if SS is any finite nonempty subset of Z×Z\mathbb{Z} \times \mathbb{Z}, then A(S)>0A(S) > 0. (For example, if S={(0,1),(0,2),(2,0),(3,1)}S = \{(0,1), (0,2), (2,0), (3,1)\}, then the terms in A(S)A(S) are 12, 12, 12, 12, 4, 4, 0, 0, 0, -1, -1, -2, -2, -4, -4.)

Dataset text Putnam 1995 to 2025. Quoted with source.

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