olymmath

Putnam 1999 A4

  • Session A

Sum the series ∑m=1∞∑n=1∞m2n3m(n3m+m3n).\sum_{m=1}^\infty \sum_{n=1}^\infty \frac{m^2 n}{3^m(n3^m+m3^n)}.

Curated text Kedlaya Putnam archive. Quoted with source.

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