olymmath

Putnam 1998

William Lowell Putnam Mathematical Competition 1998.

Session A

A1

  • Session A

A right circular cone has base of radius 1 and height 3. A cube is inscribed in the cone so that one face of the cube is contained in the base of the cone. What is the side-length of the cube?

Answer, solutions and source

A2

  • Session A

Let ss be any arc of the unit circle lying entirely in the first quadrant. Let AA be the area of the region lying below ss and above the xx-axis and let BB be the area of the region lying to the right of the yy-axis and to the left of ss. Prove that A+BA+B depends only on the arc length, and not on the position, of ss.

Answer, solutions and source

A3

  • Session A

Let ff be a real function on the real line with continuous third derivative. Prove that there exists a point aa such that f(a)⋅f′(a)⋅f′′(a)⋅f′′′(a)≥0.f(a)\cdot f'(a) \cdot f''(a) \cdot f'''(a)\geq 0 .

Answer, solutions and source

A4

  • Session A

Let A1=0A_1=0 and A2=1A_2=1. For n>2n>2, the number AnA_n is defined by concatenating the decimal expansions of An−1A_{n-1} and An−2A_{n-2} from left to right. For example A3=A2A1=10A_3=A_2 A_1=10, A4=A3A2=101A_4=A_3 A_2 = 101, A5=A4A3=10110A_5=A_4 A_3 = 10110, and so forth. Determine all nn such that 1111 divides AnA_n.

Answer, solutions and source

A5

  • Session A

Let F\mathcal F be a finite collection of open discs in R2\mathbb R^2 whose union contains a set E⊆R2E\subseteq \mathbb R^2. Show that there is a pairwise disjoint subcollection D1,…,DnD_1,\ldots, D_n in F\mathcal F such that E⊆∪j=1n3Dj.E\subseteq \cup_{j=1}^n 3D_j. Here, if DD is the disc of radius rr and center PP, then 3D3D is the disc of radius 3r3r and center PP.

Answer, solutions and source

A6

  • Session A

Let A,B,CA, B, C denote distinct points with integer coordinates in R2\mathbb R^2. Prove that if (∣AB∣+∣BC∣)2<8⋅[ABC]+1(|AB|+|BC|)^2<8\cdot [ABC]+1 then A,B,CA, B, C are three vertices of a square. Here ∣XY∣|XY| is the length of segment XYXY and [ABC][ABC] is the area of triangle ABCABC.

Answer, solutions and source

Session B

B1

  • Session B

Find the minimum value of (x+1/x)6−(x6+1/x6)−2(x+1/x)3+(x3+1/x3)\frac{(x+1/x)^6-(x^6+1/x^6)-2}{(x+1/x)^3+(x^3+1/x^3)} for x>0x>0.

Answer, solutions and source

B2

  • Session B

Given a point (a,b)(a,b) with 0<b<a0<b<a, determine the minimum perimeter of a triangle with one vertex at (a,b)(a,b), one on the xx-axis, and one on the line y=xy=x. You may assume that a triangle of minimum perimeter exists.

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B3

  • Session B

let HH be the unit hemisphere {(x,y,z):x2+y2+z2=1,z≥0}\{(x,y,z):x^2+y^2+z^2=1,z\geq 0\}, CC the unit circle {(x,y,0):x2+y2=1}\{(x,y,0):x^2+y^2=1\}, and PP the regular pentagon inscribed in CC. Determine the surface area of that portion of HH lying over the planar region inside PP, and write your answer in the form Asin⁡α+Bcos⁡βA \sin\alpha + B \cos\beta, where A,B,α,βA,B,\alpha,\beta are real numbers.

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B4

  • Session B

Find necessary and sufficient conditions on positive integers mm and nn so that ∑i=0mn−1(−1)⌊i/m⌋+⌊i/n⌋=0.\sum_{i=0}^{mn-1} (-1)^{\lfloor i/m \rfloor +\lfloor i/n\rfloor}=0.

Answer, solutions and source

B5

  • Session B

Let NN be the positive integer with 1998 decimal digits, all of them 1; that is, N=1111⋯11.N=1111\cdots 11. Find the thousandth digit after the decimal point of N\sqrt N.

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B6

  • Session B

Prove that, for any integers a,b,ca, b, c, there exists a positive integer nn such that n3+an2+bn+c\sqrt{n^3+an^2+bn+c} is not an integer.

Answer, solutions and source