olymmath

Putnam 1997 B2

  • Session B

Let ff be a twice-differentiable real-valued function satisfying f(x)+f′′(x)=−xg(x)f′(x),f(x)+f''(x)=-xg(x)f'(x), where g(x)≥0g(x)\geq 0 for all real xx. Prove that ∣f(x)∣|f(x)| is bounded.

Curated text Kedlaya Putnam archive. Quoted with source.

Solutions

Human solution Solution 1 by Manjul Bhargava, Kiran Kedlaya and Lenny Ng

The terms of the source let olymmath link to this solution but not copy it. Read the solution (Kedlaya Putnam archive).

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