olymmath

Putnam 1989 A3

  • Session A

Prove that if 11z10+10iz9+10iz−11=0,11z^{10}+10iz^9+10iz-11=0, then ∣z∣=1.|z|=1. (Here zz is a complex number and i2=−1i^2=-1.)

Curated text Kedlaya Putnam archive. Quoted with source.

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