olymmath

Putnam 1969 B3

  • Session B

The terms of a sequence TnT_n satisfy TnTn+1=n(n=1,2,3,… ) and lim⁡n→∞TnTn+1=1.T_n T_{n+1} = n (n = 1, 2, 3, \dots) \text{ and } \lim_{n \to \infty} \frac{T_n}{T_{n+1}} = 1. Find the value of πT12\pi T_1^2.

Dataset text Putnam-AXIOM. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator putnam/1969/b3 · Tag ZAQ479MY9M · Edit this page on GitHub · Keys: j next, k previous