olymmath

NMC 2013 Problem 1

  • Answer

Let (an)n≥1\left(a_{n}\right)_{n \geq 1} be a sequence with a1=1a_{1}=1 and

an+1=⌊an+an+12⌋a_{n+1}=\left\lfloor a_{n}+\sqrt{a_{n}}+\frac{1}{2}\right\rfloor

for all n≥1n \geq 1, where ⌊x⌋\lfloor x\rfloor denotes the greatest integer less than or equal to xx. Find all n≤2013n \leq 2013 such that ana_{n} is a perfect square.

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

a_{1}=1

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator nordic/2013/p1 · Tag RTSN2E2YYW · Edit this page on GitHub · Keys: j next, k previous