olymmath

JBMO 2019 Problem 3

  • Paper

Triangle ABCA B C is such that AB<ACA B<A C. The perpendicular bisector of side BCB C intersects lines ABA B and ACA C at points PP and QQ, respectively. Let HH be the orthocentre of triangle ABCA B C, and let MM and NN be the midpoints of segments BCB C and PQP Q, respectively. Prove that lines HMH M and ANA N meet on the circumcircle of ABCA B C.

Dataset text NuminaMath olympiads. Quoted with source.

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator jbmo/2019/p3 · Tag 4ADSX243YP · Edit this page on GitHub · Keys: j next, k previous