olymmath

JBMO-SL 2013 G4

    Let II be the incenter and ABA B the shortest side of a triangle ABCA B C. The circle with center II and passing through CC intersects the ray ABA B at the point PP and the ray BAB A at the point QQ. Let DD be the point where the excircle of the triangle ABCA B C belonging to angle AA touches the side BCB C, and let EE be the symmetric of the point CC with respect to DD. Show that the lines PEP E and CQC Q are perpendicular.

    Dataset text NuminaMath olympiads. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Locator jbmo-sl/2013/g4 · Tag 4568RM7J3M · Edit this page on GitHub · Keys: j next, k previous