olymmath

JBMO-SL 2011 C3

  • Answer

We can change a natural number nn in three ways:

a) If the number nn has at least two digits, we erase the last digit and we subtract that digit from the remaining number (for example, from 123 we get 12−3=912-3=9 );

b) If the last digit is different from 0 , we can change the order of the digits in the opposite one (for example, from 123 we get 321 );

c) We can multiply the number nn by a number from the set {1,2,3,…,2010}\{1,2,3, \ldots, 2010\}.

Can we get the number 21062011 from the number 1012011?

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

NO

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator jbmo-sl/2011/c3 · Tag 85HHBNTVW3 · Edit this page on GitHub · Keys: j next, k previous