olymmath

ISL 2021 G5

    Let ABCDA B C D be a cyclic quadrilateral whose sides have pairwise different lengths. Let OO be the circumcentre of ABCDA B C D. The internal angle bisectors of ∠ABC\angle A B C and ∠ADC\angle A D C meet ACA C at B1B_{1} and D1D_{1}, respectively. Let OBO_{B} be the centre of the circle which passes through BB and is tangent to ACA C at D1D_{1}. Similarly, let ODO_{D} be the centre of the circle which passes through DD and is tangent to ACA C at B1B_{1}. Assume that BD1∥DB1B D_{1} \| D B_{1}. Prove that OO lies on the line OBODO_{B} O_{D}.

    Dataset text NuminaMath olympiads. Quoted with source.

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