ISL 2019 A3
Let be a positive integer and let be a strictly increasing sequence of positive real numbers with sum equal to 2 . Let be a subset of such that the value of is minimised. Prove that there exists a strictly increasing sequence of positive real numbers with sum equal to 2 such that (New Zealand) Common remarks. In all solutions, we say an index set is -minimising if it has the property in the problem for the given sequence . Write for the complement of , and for the interval of integers such that . Note that so we may exchange and where convenient. Let and note that is -minimising if and only if it minimises , and that if and only if . In some solutions, a scaling process is used. If we have a strictly increasing sequence of positive real numbers (typically obtained by perturbing the in some way) such that then we may put . So it suffices to construct such a sequence without needing its sum to be 2 . The solutions below show various possible approaches to the problem. Solutions 1 and 2 perturb a few of the to form the (with scaling in the case of Solution 1, without scaling in the case of Solution 2). Solutions 3 and 4 look at properties of the index set . Solution 3 then perturbs many of the to form the , together with scaling. Rather than using such perturbations, Solution 4 constructs a sequence directly from the set with the required properties. Solution 4 can be used to give a complete description of sets that are -minimising for some .
Dataset text NuminaMath olympiads. Quoted with source.
Solutions
Official solution Solution 1 by the IMO Problem Selection Committee
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