olymmath

ISL 2016 G6

    Let ABCDA B C D be a convex quadrilateral with ∠ABC=∠ADC<90∘\angle A B C=\angle A D C<90^{\circ}. The internal angle bisectors of ∠ABC\angle A B C and ∠ADC\angle A D C meet ACA C at EE and FF respectively, and meet each other at point PP. Let MM be the midpoint of ACA C and let ω\omega be the circumcircle of triangle BPDB P D. Segments BMB M and DMD M intersect ω\omega again at XX and YY respectively. Denote by QQ the intersection point of lines XEX E and YFY F. Prove that PQ⊥ACP Q \perp A C.

    Dataset text NuminaMath olympiads. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Locator isl/2016/g6 · Tag A3SG7QC1TK · Edit this page on GitHub · Keys: j next, k previous