olymmath

ISL 2013 G4

    Let ABCA B C be a triangle with ∠B>∠C\angle B>\angle C. Let PP and QQ be two different points on line ACA C such that ∠PBA=∠QBA=∠ACB\angle P B A=\angle Q B A=\angle A C B and AA is located between PP and CC. Suppose that there exists an interior point DD of segment BQB Q for which PD=PBP D=P B. Let the ray ADA D intersect the circle ABCA B C at R≠AR \neq A. Prove that QB=QRQ B=Q R. (Georgia)

    Official text Transcription from NuminaMath olympiads, checked word for word against the official paper. Quoted with source.

    Official text: IMO 2013 Shortlist booklet, page 6.

    Solutions

    Official solution Solution 1 by the IMO Problem Selection Committee

    The terms of the source let olymmath link to this solution but not copy it. Read the solution (IMO official site).

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