olymmath

ISL 2013 G2

    Let ω\omega be the circumcircle of a triangle ABCA B C. Denote by MM and NN the midpoints of the sides ABA B and ACA C, respectively, and denote by TT the midpoint of the arc⁡BC\operatorname{arc} B C of ω\omega not containing AA. The circumcircles of the triangles AMTA M T and ANTA N T intersect the perpendicular bisectors of ACA C and ABA B at points XX and YY, respectively; assume that XX and YY lie inside the triangle ABCA B C. The lines MNM N and XYX Y intersect at KK. Prove that KA=KTK A=K T. (Iran)

    Dataset text NuminaMath olympiads. Quoted with source.

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