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ISL 2011 G2

  • Answer

Let A1A2A3A4A_{1} A_{2} A_{3} A_{4} be a non-cyclic quadrilateral. Let O1O_{1} and r1r_{1} be the circumcenter and the circumradius of the triangle A2A3A4A_{2} A_{3} A_{4}. Define O2,O3,O4O_{2}, O_{3}, O_{4} and r2,r3,r4r_{2}, r_{3}, r_{4} in a similar way. Prove that 1O1A12−r12+1O2A22−r22+1O3A32−r32+1O4A42−r42=0\frac{1}{O_{1} A_{1}^{2}-r_{1}^{2}}+\frac{1}{O_{2} A_{2}^{2}-r_{2}^{2}}+\frac{1}{O_{3} A_{3}^{2}-r_{3}^{2}}+\frac{1}{O_{4} A_{4}^{2}-r_{4}^{2}}=0

Dataset text NuminaMath olympiads. Quoted with source.

Official text: IMO 2011 Shortlist booklet, page 9.

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Solutions

Official solution Solution 1 by the IMO Problem Selection Committee

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