olymmath

ISL 2011 G1

    Let ABCA B C be an acute triangle. Let ω\omega be a circle whose center LL lies on the side BCB C. Suppose that ω\omega is tangent to ABA B at B′B^{\prime} and to ACA C at C′C^{\prime}. Suppose also that the circumcenter OO of the triangle ABCA B C lies on the shorter arc⁡B′C′\operatorname{arc} B^{\prime} C^{\prime} of ω\omega. Prove that the circumcircle of ABCA B C and ω\omega meet at two points.

    Dataset text NuminaMath olympiads. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Locator isl/2011/g1 · Tag GDRZDP8Z5S · Edit this page on GitHub · Keys: j next, k previous