olymmath

ISL 2009 A2

  • Answer

Let a,b,ca, b, c be positive real numbers such that 1a+1b+1c=a+b+c\frac{1}{a}+\frac{1}{b}+\frac{1}{c}=a+b+c. Prove that 1(2a+b+c)2+1(2b+c+a)2+1(2c+a+b)2≤316\frac{1}{(2 a+b+c)^{2}}+\frac{1}{(2 b+c+a)^{2}}+\frac{1}{(2 c+a+b)^{2}} \leq \frac{3}{16}

Dataset text NuminaMath olympiads. Quoted with source.

Show the answer

\frac{3}{16}

Solutions

No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

Add a solution

Locator isl/2009/a2 · Tag PYB2KH9PW4 · Edit this page on GitHub · Keys: j next, k previous