olymmath

ISL 2007 A6

  • Answer

Let a1,a2,…,a100a_{1}, a_{2}, \ldots, a_{100} be nonnegative real numbers such that a12+a22+…+a1002=1a_{1}^{2}+a_{2}^{2}+\ldots+a_{100}^{2}=1. Prove that a12a2+a22a3+…+a1002a1<1225a_{1}^{2} a_{2}+a_{2}^{2} a_{3}+\ldots+a_{100}^{2} a_{1}<\frac{12}{25} (Poland)

Dataset text NuminaMath olympiads. Quoted with source.

Official text: IMO 2007 Shortlist booklet, page 21.

Show the answer

S \leq \sqrt{\frac{5+2 \sqrt{7}}{33+6 \sqrt{7}}} \approx 0.458879

Solutions

Official solution Solution 1 by the IMO Problem Selection Committee

The terms of the source let olymmath link to this solution but not copy it. Read the solution (IMO official site).

Locator isl/2007/a6 · Tag ZTYE9B82M4 · Edit this page on GitHub · Keys: j next, k previous