olymmath

ISL 2006 G8

    Let ABCDA B C D be a convex quadrilateral. A circle passing through the points AA and DD and a circle passing through the points BB and CC are externally tangent at a point PP inside the quadrilateral. Suppose that ∠PAB+∠PDC≤90∘ and ∠PBA+∠PCD≤90∘. \angle P A B+\angle P D C \leq 90^{\circ} \text { and } \angle P B A+\angle P C D \leq 90^{\circ} \text {. } Prove that AB+CD≥BC+ADA B+C D \geq B C+A D. (Poland)

    Official text Transcription from NuminaMath olympiads, checked word for word against the official paper. Quoted with source.

    Official text: IMO 2006 Shortlist booklet, page 47.

    Solutions

    Official solution Solution 1 by the IMO Problem Selection Committee

    The terms of the source let olymmath link to this solution but not copy it. Read the solution (IMO official site).

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