olymmath

ISL 2006 G2

    Let ABCDA B C D be a trapezoid with parallel sides AB>CDA B>C D. Points KK and LL lie on the line segments ABA B and CDC D, respectively, so that AK/KB=DL/LCA K / K B=D L / L C. Suppose that there are points PP and QQ on the line segment KLK L satisfying ∠APB=∠BCD and ∠CQD=∠ABC. \angle A P B=\angle B C D \text { and } \angle C Q D=\angle A B C \text {. } Prove that the points P,Q,BP, Q, B and CC are concyclic. (Ukraine)

    Official text Transcription from NuminaMath olympiads, checked word for word against the official paper. Quoted with source.

    Official text: IMO 2006 Shortlist booklet, page 37.

    Solutions

    Official solution Solution 1 by the IMO Problem Selection Committee

    The terms of the source let olymmath link to this solution but not copy it. Read the solution (IMO official site).

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