olymmath

ISL 2006 G1

    Let ABCA B C be a triangle with incentre II. A point PP in the interior of the triangle satisfies ∠PBA+∠PCA=∠PBC+∠PCB.\angle P B A+\angle P C A=\angle P B C+\angle P C B . Show that AP≥AIA P \geq A I and that equality holds if and only if PP coincides with II. (Korea)

    Dataset text NuminaMath olympiads. Quoted with source.

    Solutions

    No solution is on olymmath yet. Official and human solutions come first when they arrive. AI solutions come after them, with a label.

    Add a solution

    Locator isl/2006/g1 · Tag W9GSSQ1DYE · Edit this page on GitHub · Keys: j next, k previous