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INMO 2005 Problem 1

  • Answer

Let MM be the midpoint of side BCB C of a triangle ABCA B C. Let the median AMA M intersect the incircle of ABCA B C at KK and L,KL, K being nearer to AA than LL. If AK=KL=LMA K=K L=L M, prove that the sides of triangle ABCA B C are in the ratio 5:10:135: 10: 13 in some order.

Dataset text NuminaMath olympiads. Quoted with source.

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\frac{a}{10}=\frac{b}{13}=\frac{c}{5}

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