IMO 2026 Problem 6
- Day 2
- Number theory
- Proof
Let be an infinite sequence of positive integers greater than . Suppose that for all positive integers , the number is the smallest positive integer greater than such that for every . Prove that there exist positive integers and such that
for every positive integer .
(Note that denotes the greatest common divisor of positive integers and .)
Official text IMO 2026 official English paper, page 2. Quoted with source.
Solutions
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