olymmath

IMO 2018

International Mathematical Olympiad 2018.

Day 1

Problem 1

  • Day 1

Let Γ\Gamma be the circumcircle of acute triangle ABCABC . Points DD and EE are on segments ABAB and ACAC respectively such that AD=AEAD = AE . The perpendicular bisectors of BDBD and CECE intersect minor arcs ABAB and ACAC of Γ\Gamma at points FF and GG respectively. Prove that lines DEDE and FGFG are either parallel or they are the same line.

Proposed by Silouanos Brazitikos, Evangelos Psychas and Michael Sarantis, Greece

Answer, solutions and source

Problem 2

  • Day 1

Find all integers n≥3n \geq 3 for which there exist real numbers a1,a2,…an+2a_1, a_2, \dots a_{n + 2} satisfying an+1=a1a_{n + 1} = a_1 , an+2=a2a_{n + 2} = a_2 and aiai+1+1=ai+2,a_ia_{i + 1} + 1 = a_{i + 2}, for i=1,2,…,ni = 1, 2, \dots, n .

Proposed by Patrik Bak, Slovakia

Answer, solutions and source

Day 2

Problem 4

  • Day 2

A site is any point (x,y)(x, y) in the plane such that xx and yy are both positive integers less than or equal to 20.

Initially, each of the 400 sites is unoccupied. Amy and Ben take turns placing stones with Amy going first. On her turn, Amy places a new red stone on an unoccupied site such that the distance between any two sites occupied by red stones is not equal to 5\sqrt{5} . On his turn, Ben places a new blue stone on any unoccupied site. (A site occupied by a blue stone is allowed to be at any distance from any other occupied site.) They stop as soon as a player cannot place a stone.

Find the greatest KK such that Amy can ensure that she places at least KK red stones, no matter how Ben places his blue stones.

Proposed by Gurgen Asatryan, Armenia

Answer, solutions and source

Problem 5

  • Day 2

Let a1a_1 , a2a_2 , …\ldots be an infinite sequence of positive integers. Suppose that there is an integer N>1N > 1 such that, for each n≥Nn \geq N , the number a1a2+a2a3+⋯+an−1an+ana1\frac{a_1}{a_2} + \frac{a_2}{a_3} + \cdots + \frac{a_{n-1}}{a_n} + \frac{a_n}{a_1} is an integer. Prove that there is a positive integer MM such that am=am+1a_m = a_{m+1} for all m≥Mm \geq M .

Proposed by Bayarmagnai Gombodorj, Mongolia

Answer, solutions and source

Problem 6

  • Day 2

A convex quadrilateral ABCDA B C D satisfies AB⋅CD=BC⋅DAA B\cdot C D = B C\cdot D A . Point XX lies inside ABCDA B C D so that

∠XAB=∠XCDand∠XBC=∠XDA.\angle X A B = \angle X C D \mathrm{and} \angle X B C = \angle X D A.

Prove that ∠BXA+∠DXC=180∘\angle B X A + \angle D X C = 180^{\circ}

Answer, solutions and source