olymmath

IMO 2017

International Mathematical Olympiad 2017.

Day 1

Problem 1

  • Day 1

For each integer a0>1a_0 > 1 , define the sequence a0,a1,a2,…a_0, a_1, a_2, \ldots for n≥0n \geq 0 as an+1={anif an is an integer,an+3otherwise.a_{n+1} = \begin{cases} \sqrt{a_n} & \text{if } \sqrt{a_n} \text{ is an integer,} a_n + 3 & \text{otherwise.} \end{cases} Determine all values of a0a_0 such that there exists a number AA such that an=Aa_n = A for infinitely many values of nn .

Proposed by Stephan Wagner, South Africa

Answer, solutions and source

Problem 2

  • Day 1

Let R\mathbb{R} be the set of real numbers. Determine all functions f:R→Rf: \mathbb{R} \rightarrow \mathbb{R} such that, for any real numbers xx and yy , f(f(x)f(y))+f(x+y)=f(xy).f(f(x)f(y)) + f(x+y) = f(xy).

Proposed by Dorlir Ahmeti, Albania

Answer, solutions and source

Problem 3

  • Day 1

A hunter and an invisible rabbit play a game in the Euclidean plane. The rabbit's starting point, A0,A_0, and the hunter's starting point, B0B_0 are the same. After n−1n-1 rounds of the game, the rabbit is at point An−1A_{n-1} and the hunter is at point Bn−1.B_{n-1}. In the nthn^{\text{th}} round of the game, three things occur in order:

[list=i] []The rabbit moves invisibly to a point AnA_n such that the distance between An−1A_{n-1} and AnA_n is exactly 1.1. []A tracking device reports a point PnP_n to the hunter. The only guarantee provided by the tracking device to the hunter is that the distance between PnP_n and AnA_n is at most 1.1. [*]The hunter moves visibly to a point BnB_n such that the distance between Bn−1B_{n-1} and BnB_n is exactly 1.1. [/list] Is it always possible, no matter how the rabbit moves, and no matter what points are reported by the tracking device, for the hunter to choose her moves so that after 10910^9 rounds, she can ensure that the distance between her and the rabbit is at most 100?100? Proposed by Gerhard Woeginger, Austria

Answer, solutions and source

Day 2

Problem 4

  • Day 2

Let RR and SS be different points on a circle Ω\Omega such that RSRS is not a diameter. Let ℓ\ell be the tangent line to Ω\Omega at RR . Point TT is such that SS is the midpoint of the line segment RTRT . Point JJ is chosen on the shorter arc RSRS of Ω\Omega so that the circumcircle Γ\Gamma of triangle JSTJST intersects ℓ\ell at two distinct points. Let AA be the common point of Γ\Gamma and ℓ\ell that is closer to RR . Line AJAJ meets Ω\Omega again at KK . Prove that the line KTKT is tangent to Γ\Gamma .

Proposed by Charles Leytem, Luxembourg

Answer, solutions and source

Problem 5

  • Day 2

An integer N≥2N \ge 2 is given. A collection of N(N+1)N(N + 1) soccer players, no two of whom are of the same height, stand in a row. Sir Alex wants to remove N(N−1)N(N - 1) players from this row leaving a new row of 2N2N players in which the following NN conditions hold: ( 11 ) no one stands between the two tallest players, ( 22 ) no one stands between the third and fourth tallest players,     ⋮\;\;\vdots ( NN ) no one stands between the two shortest players.

Show that this is always possible.

Proposed by Grigory Chelnokov, Russia

Answer, solutions and source

Problem 6

  • Day 2

An ordered pair (x,y)(x, y) of integers is a primitive point if the greatest common divisor of xx and yy is 11 . Given a finite set SS of primitive points, prove that there exist a positive integer nn and integers a0,a1,…,ana_0, a_1, \ldots , a_n such that, for each (x,y)(x, y) in SS , we have: a0xn+a1xn−1y+a2xn−2y2+⋯+an−1xyn−1+anyn=1.a_0x^n + a_1x^{n-1} y + a_2x^{n-2}y^2 + \cdots + a_{n-1}xy^{n-1} + a_ny^n = 1. Proposed by John Berman, United States

Answer, solutions and source