olymmath

IMO 1985 Problem 5

  • Day 2

A circle with center OO passes through the vertices AA and CC of the triangle ABCABC and intersects the segments ABAB and BCBC again at distinct points KK and NN respectively. Let MM be the point of intersection of the circumcircles of triangles ABCABC and KBNKBN (apart from BB ). Prove that ∠OMB=90∘\angle OMB=90^{\circ} .

Dataset text AI-MO AoPS. Quoted with source.

Official text: IMO 1985 official English paper, page 1.

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