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IMO 1965 Problem 5

  • Day 2

Consider △OAB\triangle OAB with acute angle AOBAOB . Thorugh a point M≠OM \neq O perpendiculars are drawn to OAOA and OBOB , the feet of which are PP and QQ respectively. The point of intersection of the altitudes of △OPQ\triangle OPQ is HH . What is the locus of HH if MM is permitted to range over

a) the side ABAB ;

b) the interior of △OAB\triangle OAB .

Dataset text AI-MO AoPS. Quoted with source.

Official text: IMO 1965 official English paper, page 1.

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