olymmath

IMO 1963

International Mathematical Olympiad 1963.

Day 1

Problem 2

  • Day 1

Point AA and segment BCBC are given. Determine the locus of points in space which are vertices of right angles with one side passing through AA , and the other side intersecting segment BCBC .

Answer, solutions and source

Problem 3

  • Day 1

In an nn -gon A1A2…AnA_{1}A_{2}\ldots A_{n} , all of whose interior angles are equal, the lengths of consecutive sides satisfy the relation a1≥a2≥⋯≥an.a_{1}\geq a_{2}\geq \dots \geq a_{n}. Prove that a1=a2=…=ana_{1}=a_{2}= \ldots= a_{n} .

Answer, solutions and source

Day 2

Problem 4

  • Day 2

Find all solutions x1,x2,x3,x4,x5x_1, x_2, x_3, x_4, x_5 of the system x5+x2=yx1x_5+x_2=yx_1 x1+x3=yx2x_1+x_3=yx_2 x2+x4=yx3x_2+x_4=yx_3 x3+x5=yx4x_3+x_5=yx_4 x4+x1=yx5x_4+x_1=yx_5 where yy is a parameter.

Answer, solutions and source

Problem 5

  • Day 2

Prove that cos⁡π7−cos⁡2π7+cos⁡3π7=12\cos{\frac{\pi}{7}}-\cos{\frac{2\pi}{7}}+\cos{\frac{3\pi}{7}}=\frac{1}{2}

Answer, solutions and source

Problem 6

  • Day 2

Five students A,B,C,D,EA, B, C, D, E took part in a contest. One prediction was that the contestants would finish in the order ABCDEABCDE . This prediction was very poor. In fact, no contestant finished in the position predicted, and no two contestants predicted to finish consecutively actually did so. A second prediction had the contestants finishing in the order DAECBDAECB . This prediction was better. Exactly two of the contestants finished in the places predicted, and two disjoint pairs of students predicted to finish consecutively actually did so. Determine the order in which the contestants finished.

Answer, solutions and source