EGMO 2024 Problem 6
- Day 2
- Answer
Problem. Find all positive integers for which there exists a degree polynomial with real coefficients such that there are at most different values among d).
Remark 1 You can add a constant to a polynomial satisfying the conditions and obtain another polynomial satisfying the conditions.
Remark 2 This problem is equivalent to: Find all positive integers for which there exists a polynomial of degree that takes at most different values at members of a an arithmetic progression with (different) terms. The answer to this EGMO problem implies a solution to this more general problem by scaling and translating, and the general result solves the EGMO problem as a special case. This means that instead of working with we have the option of working with a region that is symmetric about the origin. Irrespective of the parity of we can use the integers which run from to inclusive.
The advantage of using an arithmetic progression which is symmetric about the 0 is that is a polynomial which works for the problem if, and only if, is a polynomial which works for the problem. This means that working at one end of the run of integers is the reflection of the activity at the other end. T Remarks dismissing the cases at the other end of the run as similar now become obviously correct rather than having to be studied separately.
Dataset text NuminaMath olympiads. Quoted with source.
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d \leq 3
Solutions
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